New Delhi: Team India Former selector Sarandeep Singh believes that Virat Kohli’s army will come with 4 fast bowlers for the ICC World Test Championship Final against New Zealand in Southampton. So he should include Shardul Thakur in the playing XI instead of Mohammad Siraj.
‘Prefers Shardul because of batting’
Sarandeep Singh’s tenure as national selector was completed with the tour of Australia earlier this year. He gave preference to Shardul Thakur over Mohammad Siraj because of his batting talent. Shardul had presented a good example of this skill in Australia.
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Team India can field 2 spinners
According to the current situation, Team India can go with 3 fast bowlers and 2 spinners Ravichandran Ashwin and Ravindra Jadeja in the match starting from June 18.
‘Shardul could be the fourth pacer’
Sarandeep Singh told PTI, ‘If it is cloudy then you can play with Ishant Sharma, Jasprit Bumrah and Mohammed Shami with an extra fast bowler. I will choose Shardul as the fourth fast bowler although Siraj has also done well.
Benefits of Incorporating Shardul Thakur
“You also need batting options down the order and Shardul provides that option. The bowlers will also get help in Southampton and Shardul can swing the ball. He has many years of experience in domestic cricket and has a very sharp mind when it comes to cricket. Sarandeep said, ‘If the fourth fast bowler is selected, then Jadeja will have to sit out. Ashwin should play because there are a lot of left-handed batsmen in the New Zealand team.